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5x^2-98x-1176=0
a = 5; b = -98; c = -1176;
Δ = b2-4ac
Δ = -982-4·5·(-1176)
Δ = 33124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{33124}=182$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-98)-182}{2*5}=\frac{-84}{10} =-8+2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-98)+182}{2*5}=\frac{280}{10} =28 $
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